(4x^2)^2=16/81

Solution for (4x^2)^2=16/81 equation:

(4x^2)^2=16/81

We move all terms to the left:

(4x^2)^2-(16/81)=0

We add all the numbers together, and all the variables

4x^2^2-(+16/81)=0

We get rid of parentheses

4x^2^2-16/81=0

We multiply all the terms by the denominator


4x^2^2*81-16=0

Wy multiply elements

324x^2-16=0

a = 324; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·324·(-16)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*324}=\frac{-144}{648}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*324}=\frac{144}{648}
=2/9
$